Monday, July 22, 2019

Sensitivity Analysis and its Application for Optimal Steel Beam Design per IS 800:2007


Definition - sensitivity analysis:

Sensitivity analysis is the technique used to determine how independent variables will impact a particular dependent variable under a given set of assumptions (https://www.edupristine.com/blog/all-about-sensitivity-analysis).


Problem definition:

From IS 800:2007 Section 8.2.2, we have the following formula for determining the moment of resistance of a laterally unsupported beam.





Where bb= 1.0 for plastic and compact sections 
                  = Ze/Zp for semi-compact sections

Zp= plastic section modulus
Ze= elastic section modulus

fbd= design bending compressive stress

The parameter fbd  in turn depends on fcr,bdefined by IS 800:2007 as "extreme fiber bending compressive stress". The relation between fbd  and fcr,b is given in the form of formulae in Section 8.2.2 of IS 800:2007 and the values of fbd for a given fcr,b are tabulated in Table 14 of the standard for standard rolled I-sections and welded doubly symmetric I sections.

IS 800:2007 has the following simplified equation for fcr,b:







From the above, there are the following three parameters that influence fcr,b:
  • E = Modulus of elasticity
  • Slenderness ratio LLT/ry where LLT is the effective length of the beam for lateral torsional buckling and ris the radius of gyration about minor axis.
  • hf/twhere hf is the center-to-center distance between flanges and tis the flange thickness.
Now let us determine the input parameter that influences the output most.


Discussion on the Input Parameters:


Out of the above parameters, the value of E is something that has very minor variation and a specific value of 2.05x10is prescribed by IS 800:2007 (Section 2.2.4.1) for design purpose. Also from the equation for fcr,b, we understand that the relationship between fcr,b and E is linear, which means the variation in fcr,b will be very minor even if we play with the value of E which is more or less constant.

The remaining two parameters i.e. LLT/rand hf/tcan vary significantly.

Hence we consider LLT/rand hf/tfor our sensitivity studies.


Example:


ISMB400 beam is considered as a bench mark section. To start with, an LLT of 2.0 m is considered.

The below are the properties of ISMB400 with an initial LLT of 2.0 m and corresponding LLT/rratio.

Section
Unit weight (kg/m)
Grade
Yield strength fy (Mpa)
 LLT(m)
ry (mm)
Depth (mm)
tf (mm)
hf (mm)
LLT/ry
hf/tf
fcr,b (MPa)
ISMB400
61.6
E250
250
2
28.2
400
16
384
70.9
24
530.3424

Analysis Approach:


The value of fcr,b is calculated for the following variations:
1. Variations in LLT/rkeeping hf/tf  constant
2. Variations in hf/tf  keeping LLT/rconstant.

The LLT is varied from 0.5 times the initial LLT of 2m to twice that, i.e. between 1m and 4m. The LLT/rvalue also varies in the same proportion.

The hf/tvalue is varied from 0.5 times the initial value of 24 which is for the ISMB400 to twice that value, i.e. between 12 and 48.


Assumptions:

  • When the hf/tvalue is varied, it is assumed that the beam section is re-proportioned in such a way that the rvalue and hence the LLT/ry value remains the same.
  • When the rvalue is varied, it is assumed that the beam section is re-proportioned in such a way that the value of hf/t remains the same.
  • Above two assumptions mean assumption of independence between LLT/rand hf/t.

Results:

Tabulation of results:



fcr,b (MPa)
Row mean (MPa)


hf/tf


12
18
24
36
48

LLT/ry
35.5
2121
1934
1864
1812
1794
1905
53.2
1108
943
878
828
810
913
70.9
733
590
530
484
466
561
106.4
437
326
277
236
219
299
141.8
313
224
183
147
133
200
Column mean (MPa)
942
803
746
701
684


Data visualization:

Scatter plots:























































Box plots:

For better visualization of data, below box plots have been plotted.

hf/tf  =12 and varying LLT/ry                                   hf/tf  =18 and varying LLT/ry              

      

hf/tf  =24 and varying LLT/ry                                              hf/tf  =36 and varying LLT/r

                                    

 hf/tf  =48 and varying LLT/r

     

 LLT/ry =35.5 and varying hf/tf                                        LLT/ry =53.2 and varying hf/t                                  

LLT/ry =70.9 and varying hf/tf                                    LLT/ry =106.4 and varying hf/tf


                           

                 

   LLT/ry =141.8 and varying hf/tf

Discussions, Data Analytics and Results Interpretation:

Data Analytics:


The above data tells us that there is not much variation in the fcr,b  value across the columns (hf/tf) compared to the variation across the rows (LLT/ry).

Also we find that the means of the columns are close by while there is a lot of variation in the means of the rows.

From the scatter plots, we see negative correlation between each of the independent variables i.e. LLT/rand hf/tf,  and the dependent variable i.e. fcr, . This is as expected from the equation for fcr,b.

ANOVA and discussion of its suitability:


To analyze the variation further, let us perform ANOVA. One may say both LLT/rand hf/tf are continuous and hence the applicability of ANOVA is not appropriate.

Now the structural engineer in us has to wake up! Even though LLT/rand hf/tf are continuous variables, we have collected data against discrete data points. This is similar to how a large structural model is discretized into distinct elements in finite element method.

When the range of the data is sufficiently large, we can study if there is any variation. If the data points are centered around a particular value, then it makes no sense to perform an ANOVA.

Also the number of data points has to be sufficiently large for accurate inference. However, in our case, we have limited to 5x5 matrix of LLT/rand hf/tf values. Plotting the data over a larger number of data points conveyed to me that the basic shape of the graph doesn't change much in this particular case.

Single factor ANOVA is preferred as we are interested in which particular parameter between the two viz. LLT/rand hf/tf influences the design most.

By performing single factor ANOVA across the rows and across the columns in Excel, below are the results obtained.

Anova Case 1: 
Single Factor - hf/tf
SUMMARY
Groups Count Sum Average Variance
hf/tf = 12 5 4711.4 942.3 528355.7
hf/tf = 18 5 4016.6 803.3 476734.1
hf/tf = 24 5 3732.4 746.5 462615.0
hf/tf = 36 5 3507.4 701.5 455372.0
hf/tf = 48 5 3422.3 684.5 453788.0
ANOVA
Source of Variation SS df MS F   P-value     F crit
Between Groups 215994.5 4 53998.63 0.113592 0.976246 2.866081
Within Groups 9507459 20 475372.9
Total 9723453 24


Anova Case 2: 
Single Factor LLT/ry
SUMMARY
Groups Count Sum Average Variance
LLT/ry= 35.5 5 9525.526 1905.105 17570.41
LLT/ry= 53.2 5 4567.121 913.4242 14410.53
LLT/ry= 70.9 5 2802.828 560.5657 11619.54
LLT/ry= 106.4 5 1494.602 298.9204 7620.852
LLT/ry= 141.8 5 1000.051 200.0102 5211.85
ANOVA
Source of Variation SS df MS F      P -value   F crit
Between Groups 9497721 4 2374430 210.3754 4.9E-16 2.866081
Within Groups 225732.7 20 11286.64
Total 9723453 24

We accept the null hypothesis for case 1 and reject it for case 2.

Result interpretation:

  1. For a four times variation in LLT/ry, the value of maximum fcr,b is 6.78 times higher than the minimum fcr,b when hf/t= 12. This further increases to 13.53 times when hf/t= 48.
  2. For a four times variation in hf/tf, the value of maximum fcr,b is 1.18 times higher than the minimum fcr,b when LLT/ry  = 35.5. This further increases to 2.36 times when LLT/r= 141.8.
  3. From the ANOVA, the difference in the means of  fcr,b  across varying values of hf/tis statistically insignificant with a very high p-value of 0.976, while it is very significant across varying values of LLT/rwith a nearly zero value of p.

Conclusions:

  1. From the above, it can be established that the parameter LLT/rinfluences the fcr,b value much more than the parameter hf/tf.
  2. From the above conclusion, it can be inferred that by increasing the rvalue by using a wider flange beam, the beam design can be optimized.
  3. The same set of conclusions can be easily established by taking up similar studies for beams of other standard/non-standard sizes, both rolled and welded. 




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